DSC_0012 Zach Doty PostgreSQL cover photo

PostgreSQL Intermediate Skills Test

Hey there, SQL-ites. Time for another (yes, another!) PostgreSQL skills challenge. It’s our last stop before moving into more intermediate and advanced PostgreSQL skills, such as JOINS.

If you’re just joining this series on SQL, we previously covered the HAVING statement & GROUP BY. Here’s the home page of our journey in learning PostgreSQL. Today, we do a more rounded knowledge check of older PostgreSQL statements, such as SELECT WHERE, COUNT & ORDER BY.

We have 3 problems, and provide the winning code for each, based on our sample database. In the past, I’ve given more explanation to the problems, but because I’m trying to get some traction myself in moving forward, we’ll only have problem & solution laid out here.

Alright, let’s go!

1. Return the customer IDs of customers who have spent at least $110 with the staff member who has an ID of 2.

The answer should be customers 187 and 148.

SELECT customer_id, SUM(amount)
FROM payment
WHERE staff_id=2
GROUP BY customer_id
HAVING SUM(amount) >110;


2. How many films begin with the letter J?

The answer should be 20.


WHERE title LIKE ‘J%’;


3. What customer has the highest customer ID number whose name starts with an ‘E’ and has an address ID lower than 500?

The answer is Eddie Tomlin.

SELECT customer_id, first_name, last_name, address_id
FROM customer
WHERE address_id <500 AND first_name LIKE ‘E%’
ORDER BY customer_id DESC;


We’ll see you on the other side soon, for some JOINS awesomeness. 🙂

DSC_0300 Zach Doty Cover Photo for HAVING PostgreSQL Clause

The HAVING Clause in PostgreSQL

Howdy SQL-ites! Welcome back to our next step in learning SQL. After a long hiatus, we recently stumbled our way through some intermediate SQL statement challenges, namely on GROUP BY.

Today, we’re back in the flow, and learning about the HAVING clause in PostgreSQL.


About the HAVING Clause in PostgreSQL

The HAVING clause is most often seen as a helper with the GROUP BY statementGROUP BY was pretty awesome, right? How might we improve upon it?

Let’s consider two concepts:

  1. Our occasional parallels of PostgreSQL to Excel, and,
  2. Our previous intermediate challenge example.

Relating PostgreSQL’s GROUP BY to Excel

If we hearken back to our first encounter with GROUP BY, we compared GROUP BY to pivot tables. Specifically, if we have a big data table that records data of recurring themes, e.g., you customer base, it can be helpful to manipulate as aggregated and assembled, vs. raw.

However, GROUP BY is only an intermediate step in data analysis. If we think about our final challenge in the last post, we had to limit the results to 5. Even if we group data, it’s neither segmented nor useful toward analysis.

Thus, we need an additional method for winnowing down our GROUP BY results.


Meet the HAVING Clause

So, about the HAVING clause. It’s most often used in tandem with GROUP BY to filter out data rows that don’t meet a certain condition. Think of it as similar to the WHERE function, just an accompaniment to GROUP BY.


Let’s take a look at basic syntax:

SELECT column, aggregate(column_2)

FROM table

GROUP BY column

HAVING condition;


Off the bat, we should this is extremely familiar if we’ve covered GROUP BY. The differentiation is the additional HAVING condition at the end. This condition could be something like, HAVING sum(column_2) less than 50.

The Difference Between WHERE and HAVING

Some of you sharp folks may want to know, “what’s the difference between WHERE and HAVING?” That would be an excellent question. Here’s the difference:

The WHERE clause sets conditions on individual rows, before the GROUP BY clause has been applied. The HAVING clause specifies conditions on grouped rows, created by the GROUP BY clause.

Let’s run some examples.


Using the HAVING Clause in PostgreSQL

Here’s our first example, very similar to our previous skills challenge:

SELECT customer_id, SUM(amount)
FROM payment
GROUP BY customer_id
HAVING SUM(amount) > 150;

Above, we have added another segmentation layer with the HAVING clause.

You can see we’re pulling information about how much our customers have paid us. Further, we specify that we only want to see customers with a lifetime purchase amount of greater than $150.


Let’s look at another example of the HAVING clause. Say for example, we want to know which store has served the most customers. Below, we’ll execute the following code:

SELECT store_id, COUNT(customer_id)
FROM customer
GROUP BY store_id
HAVING COUNT(customer_id) >275;

Above, we’ve selected both the store and customer ID columns from the customer table. Further, we group by the store ID, because we want store-level data, but we only want to see the stores which have served more than 275 customers. Below, we can see only store has done so. 🙂


Combining Usage of the WHERE & HAVING Clauses

We mentioned earlier the WHERE and HAVING clauses are different, somewhat in function, but mostly in order of execution. Here’s what we didn’t say: you can actually use them in tandem. There is a great theoretical use case for this, unfortunately our sample database is a bit small, but here goes.

Let’s think about the film table (used in previous examples.) Perhaps we want to analyze the films, by rental rate, but only films with certain ratings. For example, perhaps we’re no longer interested in carrying NC-17 films, but still want to get an aggregated view of on average, how much each films rents for, by rating. Additionally, we want to see which ratings, if any, have an average rental rate of less than $3.

Here’s the code we would use:

SELECT rating, ROUND(AVG(rental_rate),2)
FROM film
WHERE rating IN (‘R’,’G’,’PG’,’PG-13′)
GROUP BY rating
HAVING AVG(rental_rate)<3;



Wrap Up

Alright, that concludes our section for today. It feels good to be back. 🙂

Hopefully you found this section on the HAVING PostgreSQL statement useful. If you need to backtrack or further explore, here are some useful/recent links:

DSC_0006 Zach Doty Intermediate GROUP BY SQL Skills Challenge Cover Photo

Intermediate SQL Skills Challenge: GROUP BY

Hey there SQL-ites! Wow, it’s been awhile since I’ve last posted. Work has been crazy busy again, and just life in general. Sure feels good to be back, learning again! I’m daringly dropping straight back into my learnings from where we left off…in April!? Crazy.

Anyway, let’s get back to brass tacks. Before life and work got really crazy for me, we covered:

Another quick recap note, we’ve been using the famous DVD rental training database for our work. On to the good stuff.


GROUP BY SQL Skills Challenge #1

Let’s say it’s time for quarterly reviews, who doesn’t love evaluations? ¯_(ツ)_/¯ Implement your knowledge of GROUP BY against the following problem:

We need to figure out how much revenue our employees have realized from DVD rentals, and how many transactions each handled.


GROUP BY SQL Skills Answer #1

Let’s talk through the problem and dissect it before presenting code. “A problem well-stated is a problem-half solved” – paraphrase of some smart person.

  1. We’re talking about revenue, so we’ll need to be dealing with the payment table.
  2. We’re evaluating employees (staff), SUM of revenue, and COUNT of transactions.
  3. If we’re aggregating this data, we’re GROUPing BY employee.
  4. We’re also ORDERing the employees BY who handled the most transactions.

That said, here’s the code:

SELECT staff_id, SUM(amount), COUNT(amount)
FROM payment
GROUP BY staff_id

…with our results!


GROUP BY SQL Skills Challenge #2

Well done on your challenge! Here’s the second:

It’s time to do inventory, flashbacks of retail and restaurant wonder for all of us. 🙂

In the name of forecasting and planning, we need to figure out the average replacement cost of our movies, by rating.


GROUP BY SQL Skills Answer #2

Ok, let’s walk through our problem.

  1. We need to use the film database here, since we’re gathering information on the movies.
  2. We’re GROUPing our films BY rating
  3. We’re using an aggregate function to determine the average replacement cost of each rating.

Drum roll, here’s a winning code snippet:

SELECT rating, AVG(replacement_cost)
FROM film
GROUP BY rating
ORDER BY AVG(replacement_cost) DESC;

With the output:


Are there more challenges we should be covering? Yes. However, I’m trying to do better about getting more sleep these days. Unlike past SQL articles, it’s still (barely) before midnight. So we’ll take a quick breather, possibly update this article, but definitely keep moving forward. Cheers!


Update- 8/20/2017 —

GROUP BY SQL Skills Challenge #3!

Alright SQL-ites. After getting some rest, I’ve regrouped a few days later to cover the last challenge:

From our database, we want to get the customer ID’s of the top 5 customers, by money spent, so we can send them a thank you for their business!


GROUP BY SQL Skills Answer #3

Let’s diagnose the problem.

  1. If we’re gathering revenue information, we’ll need to use the payment table.
  2. If we’re getting the top spending customers, we’ll need to GROUP all transactions BY customer ID
  3. To see the top 5 paying customers, we’ll want to ORDER the results BY the SUM of payment amount.

Considering the above, here’s our code:

SELECT customer_id, SUM(amount)
FROM payment
GROUP BY customer_id

DSC_0045 Zach Doty Cover Photo Group By SQL Statement Function

GROUP BY SQL Statement

Introducing the GROUP BY SQL Statement in PostgreSQL

‘Ello SQL geeks! Welcome back to our SQL learning journey. We left off with a beginner SQL skills challenge and the aggregate SQL functions: MIN, MAX, AVG and SUM. Today we’re looking at the GROUP BY statement. We’ll learn about this function in PostgreSQL and walk through usage of this handy SQL statement.


About the GROUP BY SQL Statement/Clause

From my simple understanding, GROUP BY functions like a hybrid of the following:

  • SELECT DISTINCT keyword (If used without an aggregate function like SUM), and,
  • An Excel pivot table, rolling up aggregate figures (Count, Sum, Average, etc.) into unique rows

If you’re familiar with Excel Pivot tables, then you’ll recognize here the power of this function.


Let’s take a look at some examples to clarify.


First Look at Using the GROUP BY Function

To better illustrate the power of GROUP BY, we’ll first show its usage without aggregate functions. Consider the following:

If we query the address table of our sample database with a generic SELECT * FROM address; we get back an atrocious 605 rows of data. Aggregate and useless!


In contrast, if we call the GROUP BY function, we’ll get back a cleaner output, with fewer rows – only unique values returned. While this is an incremental improvement to analyzing data, there’s much left to be desired.



What’s missing here? How about that pivot table-esque functionality? This is where the power of using GROUP BY with aggregate functions gets awesome.

Using the GROUP BY SQL Statement with Aggregate Functions

As with most analysis, a single data point or data series rarely holds significant insight value on its own. Let’s drive home that point by leveraging the GROUP BY statement with the SUM aggregate function. Below, we compare the ratings of films in our sample database in aggregate by replacement cost. Perhaps this could serve in-store strategies for loss prevention.

SELECT rating, SUM(replacement_cost)
FROM film
GROUP BY rating;


If we extend this functionality to more real world examples, we could use the following for GROUP BY:

  • Grouping page-level / URL data to roll up clickstream analytics data
  • Large scale analysis of CRM data for customer segmentation analysis
  • Analyzing returns for financial data

The list could (and I’m sure it does) go on.

Let’s take this one step further and reduce potential future workload, by building sort functionality into our query. Below, we add a line to get most expensive ratings to least.

SELECT rating, SUM(replacement_cost)
FROM film
GROUP BY rating
ORDER BY SUM(replacement_cost) DESC;


By the looks of this, no need to guard Land Before Time 8. 🙂

Extending our lesson: you can use the COUNT, AVG, and other aggregate functions to analyze as desired.


Wrap Up

Alright, this was a relatively gentle introduction into more advanced SQL functions. GROUP BY is a rather critical function, so in our next article, we’ll be doing yet another skills challenge. Joy!

Feel free to catch up on our other articles that help you learn PostgreSQL. Also, check out some how-to’s on developing Amazon Alexa skills, and a new series on getting started with Machine Learning. As always, please share with your colleagues and share thoughts in the comments below. Cheers.

SQL Aggregate Functions: Min, Max, Avg and Sum

Welcome back, SQL nerds! We’re back in action on the journey of learning SQL, after a beginner PostgreSQL skills challenge.

We’re reaching the end of basic functions and queries with this article. Based on what we’ve learned so far, we can do basic counting, filtering, sorting and pattern matching against PostgreSQL databases.

If you’re just tuning in, here’s the page on how to learn SQL, and the previous SQL article on the LIKE Statement.

Okay, enough jabber. Let’s jump in. The aggregate functions of MIN, MAX, AVG and SUM are our turning point into more complex SQL queries that involve concepts such as GROUP BY, among others.

At the same time, the functions on their own aren’t super complicated. Because we’re ass-u-ming you’re familiar with the general concepts of minimum, maximum, etc., we’re going to forgo conceptual and syntax explanations for demos.


AVG Aggregate Function

As we level up in SQL, we’re going to do less and less explaining / handholding / screenshots. That said, we’re going to explore our DVD rental data set for a table with a nice numerical component that would make good use of the functions.

We did a SELECT * FROM film LIMIT 15; to get a peek at the columns. For the purposes of this exercise, the replacement_cost column will do nicely.

To get the AVG:

SELECT AVG(replacement_cost) FROM film;


Using ROUND for Decimal Place Control

You’ll notice in the example above that we got 3 decimal places on what’s supposed to be a dollar amount. How do we fix that? Glad you asked. Meet the ROUND function.

We pass in the target value (average of replacement_cost) and mandate the number of decimal places we’d like returned. Below:

SELECT ROUND( AVG(replacement_cost), 2) FROM film;



MIN Aggregate Function

To find the minimum value in a given column:

SELECT MIN(replacement_cost) FROM film;



MAX Aggregate Function

To find the maximum value in a given column:

SELECT MAX(replacement_cost) FROM film;



SUM Aggregate Function

To find the maximum value in a given column:

SELECT SUM(replacement_cost) FROM film;




Alright, that was a relatively quick article! Hopefully this was a reprieve from more involved sections in the past. We should find that as we continue to strengthen our core PostgreSQL  capabilities, these articles and our SQL queries should be easier and easier. If you found this article interesting, you might enjoy a new section on how to get started in machine learning. Cheers.




DSC_0007 Zach Doty Cover Photo for Beginner PostgreSQL Skills Challenge

Beginner SQL Skills Challenge!

Howdy, SQL geeks. Hope this post finds you swell!

Over the past few months, we’ve gained a ton of ground in learning SQL, or at least I have. 🙂

Let’s take a moment to:

  1. Test our knowledge of SQL skills learned thus far
  2. Start seeing SQL queries less as statements of code, and more as real world business challenges

In this article, we’ll have a recap plus three sections:

  • Recap of the training database we’ve been working with
  • General statements of each business problem
  • Hints and thoughts about how to approach each problem
  • Solutions to each problem


Recap: Our Training Database

Our training database is a best/old faithful. We’ve been using the surprisingly popular DVD rental database in a .tar file for our practice database.

Contained within this databases are various tables with fictitious information, including: customer information, film production information, business/pricing information and so forth.

In our challenges, we’ll execute various SQL queries to extract pieces of insight for business tasks. It’s assumed in this article that you’ve installed PostgreSQL via pgAdmin and have followed this article series so far, using the DVD rental training database.

Without further ado, let’s begin.


The SQL Challenges

Alright, here we go:

  1. How rentals were returned after July 17, 2005?
  2. How many actors have a last name that starts with the letter A?
  3. How many unique districts are represented in the customer database?
  4. Can you return the actual list of districts from challenge #3?
  5.  How many films have a rating of R and a replacement cost between $5 and $15?
  6. How many films have the word Truman somewhere in the title?


How to Approach the Challenges

Right, then. In this section, we’ll add some color commentary (read: hints) to our challenges. This should help you understand the mechanics of the solution, while ensuring you can’t see the answers all in one screen. 😉


Challenge 1: Rentals Returned After July 17, 2005

As with all challenges, a problem well stated is half (or more) solved. So let’s look at the high levels of the ask, and work our way down. We need information on rentals, so this means we’ll probably be querying the rentals table.

We would want to first examine the rentals table in a concise manner by doing:


Once you’ve surveyed the table, we really only need one column returned (pun not intended) and we only want the sum figure of returns, where (HINT!!) the return date was after (think a logical operator here) July 17, 2005.


Challenge 2: Actors That Have a Last Name Beginning with “A”

Like our first challenge, let’s work from the “top down”. We need actor information, so querying the actor table would be a great place to start. Similar to last time, we need a count of values matching a condition. The difference versus challenge #1  is we need to find match a pattern like or such as an actor’s last name that begins with the letter A.


Challenge 3: Number of Unique Districts in the Customer Database

The title and description could cause some confusion here. You may need to do some basic SELECT * FROM table_name LIMIT X; queries to make sure you’ve got the right table. Once you do, we’re looking for an amount of distinct values in the database. Order of operations matters.


Challenge 4: Returning the Actual Lists of Districts from Challenge #3

Not much to hint at here – getting challenge #3 is the key here. You’ll really only be simplifying the correct query in challenge #3 to get the correct answer here.


Challenge 5: Cheap, (Mildly) Naughty Films

This one might be the longest query yet in this challenge. So we’re looking up film information, thus should know which table to query. We’re returning a value where a certain rating must be returned, and (HINT) we need to layer in one more lens of qualification. That lens dictates we specify a range between (cough, hint!) two values.


Challenge 6: Where in the World are Films Containing “Truman”?

This challenge is more of a recency test than retention of older concepts. You’ll need to employ pattern matching again for this business challenge/query to find titles that have some match like Truman in the title.



Challenge Solutions

Is that your final answer? Below are the queries, with screenshots of what I did.


Solution 1: Rentals Returned After July 17, 2005

SELECT COUNT(return_date) FROM rental
WHERE return_date > ‘2005-07-17’;



Solution 2: Actors That Have a Last Name Beginning with “A”

WHERE last_name LIKE ‘A%’;



Solution 3: Number of Unique Districts in the Customer Database

SELECT COUNT(DISTINCT(district)) FROM address;



Solution 4: Returning the Actual Lists of Districts from Challenge #3

SELECT DISTINCT(district) FROM address;



Solution 5: Cheap, (Mildly) Naughty Films

WHERE rating = ‘R’
AND replacement_cost BETWEEN 5 AND 15;



Solution 6: Where in the World are Films Containing “Truman”?

WHERE title LIKE ‘%Truman%’;



Wrap Up

Well done for completing these challenges! You shall indeed pass. 🙂

Soon, we’ll be covering aggregate SQL functions, such as MIN, MAX, AVG and SUM.

If you’re just joining us, here’s a running list of our articles so to date (4/16/2017):


DSC_0104 Zach Doty Cover Photo for Learning LIKE SQL Statement

The LIKE Statement: SQL Statement Fundamentals

Howdy folks! We are overdue for another installation of SQL learning. I’ve slept a few times since the past couple of articles on how to learn SQL. Previously, we talked about the IN Statement, BETWEEN statement, and ORDER BY clause.

In this article, we’ll learn how to execute the LIKE statement in SQL queries. Let’s jump in.


About the LIKE Statement & Why it’s Important

Have you ever worked with a data set that’s overwhelmingly large  or complex? Or overwhelmingly large and complex? Sometimes, you need to find data, but can’t recall the exact string or values for a lookup. Or, perhaps, you’re working with a messy data output from say, Google Keyword Planner that groups a range of close variants into one value?

Say you’re looking for values related to designer clothing and designer clothes. Without a better solution, the most probable solution for you is to do a bunch of sorting, filtering, classifying and other data sleuthing at great expense to time and sanity.

The LIKE statement exists to help with the debacle of only having / knowing  part of the lookup criteria you need, courtesy of pattern matching.

PostgreSQL and many other SQL engines/platforms support the LIKE statement, which functions a bit like the below. (Pun not intended.)


SELECT keyword, search volume

FROM table

WHERE keyword LIKE ‘cloth%’


The above tells pgAdmin / PostgreSQL to get the keyword and search volume columns from table, where the keyword values match values that begin with ‘cloth’ and are followed by anything else, the percent sign. The combination of calling out a text string with an operate is known as a pattern.

When you execute the LIKE statement in a SQL query, pgAdmin will begin reading through the table rows to see if the pattern you’ve specified returns any matches. For the season marketing technology folks, this functionality sure does resemble regex in some ways.

However, there are some differences.

  • Here, instead of the * character being wildcard, the % sign serves as a wildcard matching all characters.
  • If you want to match a single character, the underscore character is used.


LIKE Statement Syntax & Examples

Let’s try some examples. Below, we’ll call on the faithful DVD rental practice database, and run a query for customers that have first names like Jen. (Jennifer, Jenny, etc.) Our below code produces the following result.

SELECT first_name,last_name

FROM customer

WHERE first_name LIKE ‘Jen%’;



That being considered, there are other ways we can use the like statement. Above, we used a wildcard to match any endings to a particular string.

Conversely, we could execute a SQL query that specifies a certain ending value, with the wildcard preceding. If we extend that example to such a query below, we should see the following result:

SELECT first_name,last_name

FROM customer

WHERE first_name LIKE ‘%y’;



Above, we’ve flipped the tables so we capture every possible beginning condition under this pattern. Also important to note, the patterns aren’t limited beginnings or ends. You can use this wildcard in the middle, etc. Consider the following:

SELECT first_name,last_name

FROM customer

WHERE first_name LIKE ‘%er%’;



Now, on top of all this awesomeness, realize we’ve been using it as a matching filter. We can also employ the NOT LIKE syntax to exclude values meeting the pattern we’ve specified.

Let’s mix things up a bit. We mentioned a second type of pattern matching character that we haven’t used yet: the underscore.

SELECT first_name,last_name

FROM customer

WHERE first_name LIKE ‘_her%’;



Above, we’ve made a similar ask. However, instead of requesting all possible matches, we’ve mandated SQL only return the ‘er’ string that begins with ‘h’.

To throw you a quick curveball, it’s worth noting the LIKE statement is case sensitive in its matching. Could be bad, could be good, could be neither. However, there’s a way for you to force case insensitivy on the queries. The difference in your statement appears relatively minor. Instead of using a function that calls LIKE or NOT LIKE, you’ll use ILIKE.



Hope you found this useful! Stay tuned for more SQL learnings and application. If you’re new here, visit the page on how to learn SQL. If you’re interested in more educational material, check out our ongoing series of how to develop Amazon Alexa voice search skills, and getting started with algorithmic trading. Cheers!

The IN Statement: SQL Fundamentals

Howdy, budding SQL masters! It’s been a minute since the last SQL post! I’ve taken some time to devote to Alexa Skills, some other personal housekeeping, and adopting a dog with my wife!!

Last time we talked SQL, we learned the BETWEEN statement to hone in on the exact values we wanted for a SQL query. Prior to that, we looked at the LIMIT statement to get a small return data sample and also working with ORDER BY to take sorting and filtering into our own hands.

Today we’ll be working with the IN statement.

About the IN Statement

The IN SQL operator is a companion to the WHERE clause to see if a value matches any value in a list of values. Sounds something kind of like VLOOKUP’s, yeah? The syntax of an IN statement might look like:

value IN (value1, value2)

The expression in your SQL query will return true if the value(s) you’ve specified in the query match any value in the list you’re referencing.

Sub-queries: Using the IN Statement with SELECT

The list of values is not limited to a static number or list of strings. That is, you can be a bit more dynamic and free-flowing with your query by getting the value via a SELECT statement.

This is also known as a sub-query. To illustrate, the syntax might look like:

value IN (SELECT value FROM table)

NOT IN: Not Making Fetch Happen

The IN statement has a similar corollary as the BETWEEN statement- a NOT modifier. So, we can take the inverse of a statement. (Drawing on some experience in data analysis, this can just as, if not more useful than the original statement!)

value NOT IN (SELECT value FROM table)


Sample SQL Queries for the NOT IN Statement

Alright, let’s run some sample queries using the IN statement! Here’s our first go, working again with the ever-present dvdrental sample database. Below, we are selecting rental information for customers matching only a certain ID cohort (think perhaps loyalty group?), with a few columns and sorting by descending order for the return date:

SELECT customer_id,rental_id,return_date

FROM rental

WHERE customer_id IN (1,2)

ORDER BY return_date DESC;

Below, we see our results returned as intended!


How about our corollary? If we want to add the NOT IN modifier, it’s as straightforward as you would imagine.

FROM rental

WHERE customer_id NOT IN (1,2)

ORDER BY return_date DESC;


Above, we again receive the desired result. I believe we also get a lesson in the importance of clean data here, as blank values are presented first. Let’s try one more sample query, just for kicks. We’ll switch it up ever so slightly, now working with the payment table.

SELECT city_id,city,last_update

FROM city

WHERE country_id IN (44,82,60)



Above, we’ve demonstrated that we don’t necessarily need to display a column we use in the query (country_id) and have sorted by city name in ascending order.


Wrap Up

So why the IN statement? At face value, it seems rather simplistic among SQL clauses we’ve explored thus far. Let’s consider the following.

The IN statement allows us to avoid a messy swath of values courtesy of BETWEEN (if we’re working with a proper large data set), or daisy chain list of a bunch of equals OR statements. Here’s another plus, it’s thought by some that pgAdmin / PostgreSQL will execute the IN query faster than the list of OR statements.

Alright, that’s it for today’s article. If you’re like me and need a quick refresh, revisit our page on Learning SQL that contains all the topics we’ve covered so far.


The BETWEEN Statement: SQL Statement Fundamentals

Hey there, folks! Welcome back to our journey in learning SQL. Our last few of posts covered the ORDER BY clause, LIMIT statement and the COUNT function. (See full list of SQL tutorials here.)

Today, we’re going to cover the BETWEEN statement. This is the start of some deeper material. In addition to the BETWEEN statement, we’ll also soon be covering IN and LIKE statements.


About the BETWEEN Statement

The BETWEEN statement (rather, operator) is used to match a value against a specified range of values. Maybe we want to get transactions between a certain dollar amount.

For example, value BETWEEN low AND high;

More about the BETWEEN statement. If the value is greater than or equal to the low value and  less than or equal to the high value, the expression returns true, or vice versa. Also, the BETWEEN operator can be rewritten by using the greater than or equal to ( >=) or less than or equal to ( <=) operators as the following statement.

value >= low and value <= high;

One other way to think about the BETWEEN statement is that takes two WHERE statements and lumps them into one. Think back to the WHERE statement, as we would say first:

SELECT column1 FROM table WHERE column1 >= 2 AND column1 <= 7;



Conversely, you can extend the usage of the original BETWEEN operator to NOT BETWEEN. This is similar in concept, except working toward exclusion, instead of inclusion. So, if we want to check if a given value is outside of a range, we can use the NOT BETWEEN operator as below.

value NOT BETWEEN low AND high;

Again, similarly to the double WHERE statements, NOT BETWEEN simplifies the burden into a single statement. For sanity, we’ll skip the SELECT WHERE example.


Using BETWEEN in pgAdmin / PostgreSQL

Below, we’ve taken the BETWEEN statement for a road test on our address table.

SELECT address_id,address FROM address

WHERE address_id BETWEEN 10 AND 20;


How sweet was that? Syonara, comparison operators. Conversely, if we convert the above query into a NOT BETWEEN operator, we should see the below statement return the following results.

SELECT address_id,address FROM address

WHERE address_id NOT BETWEEN 10 AND 20;


Okay, that was cool. Let’s hold up for a quick second. What about non-integer columns, such as data? Caveat: there’s a lot more to data types than our humble example below. For the purposes of this article, we can take a YYYY-MM-DD date and place the values into strings.

SELECT rental_id,rental_date,inventory_id FROM rental

WHERE rental_date BETWEEN ‘2005-05-24’ AND ‘2005-05-27’;




Alright, for those of you reading this later, it’s 2 a.m. on a Friday night / Saturday morning, and I’m about ready to call it a night. Sorry I’m not providing a better conclusion for you today. I’m excited to delve further into more complex SQL queries. Keep track of my shared journey of a beginner learning SQL. Cheers!



DSC_0163 Zach Doty Cover Photo for ORDER BY SQL Clause

ORDER BY Clause: SQL Statement Fundamentals

Welcome back to our SQL learning journey! It’s been a week and a half since my last post on using LIMIT. Work got crazy and I got the flu! 🙁 But we’re back in action. Today, we’ll delving deeper into SQL statements in PostgreSQL: ORDER BY.

Let’s jump in. Why would you need a statement that orders data? Whenever you query data from a table, PostgreSQL will by default return the rows in the order they were inserted into the table. (Read: not the order you want.)

To sort the result set from your SQL query, you can use the ORDER BY clause in the SELECT statement and specify a certain ascending or descending order.

Sample ORDER BY Clause Syntax

Here’s an example of the ORDER BY clause would look like within a SELECT statement.

SELECT column_1, column_2

FROM table_name

ORDER BY column_1 ASC / DESC;

Some important notes for the ORDER BY clause:

  • Specify the column you want to sort by with the ORDER BY clause
    • If you sort the results by multiple columns, use a comma to separate between the two columns
  • Use ASC to sort the results in ascending order
  • Use DESC to sort the results in descending order
  • Should you leave the ORDER BY clause blank, it will use ASC (ascending) by default

ORDER BY Clause Examples in SQL Statements

Alright, first up. We’ll do a basic SELECT statement, adding both ORDER BY and LIMIT clauses. Code and screen shot below. The query should select the first and last name columns from the customer table, ordered by last name ascending (A > Z), returning only the first 10 rows.

SELECT first_name,last_name  FROM customer

ORDER BY last_name ASC




Let’s try another example. What if we want to do an advanced / multiple sort? Let’s try it out, and change it up ever so slightly from the first sample query.

SELECT first_name,last_name

FROM customer

ORDER BY first_name ASC,

last_name DESC;


If we scroll down to the first set of duplicate first names, we’ll see the last name has been presented in descending order (Z > A).

More Details About the ORDER BY Clause

Did you know? In PostgreSQL, you can ORDER BY columns that aren’t explicitly selected within the SELECT statement? E.g. We could only select first and last name, but order by their address_id value. Interesting, yes? Important caveat, other SQL programs, such as MySQL, may not let you do this.


SELECT first_name FROM customer

ORDER BY last_name ASC;



Thanks for joining me and hopefully you’ve learned the essentials for the ORDER BY clause. Feel free to check out the entire journey on how to learn SQL, thanks!